In Quincke’s tube a detector detects minimum intensity. Now one of the tube is displaced by $5 \,\,cm$. During displacement detector detects maximum intensity $10$ times, then finally a minimum intensity (when displacement is complete). The wavelength of sound is .... $cm$
Diffcult
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The bigger dots represent maximas and the smaller dots represent miniimas.
One of the tube is displaced by $5cm.$
Thus total path difference arises, $x=2 \times 5 c m=10 c m$
Due to this path difference $10$ maximas occur between the end points (minimas).
$\Longrightarrow \frac{\lambda}{2}+9 \lambda+\frac{\lambda}{2}=10$
$\Rightarrow \lambda=1 \mathrm{cm}$
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