In resonance tube two successive positions of resonance are obtained at $15 \,cm$ and $48 \,cm$. If the frequency of the fork is $500 \,cps$, the velocity of sound is ......... $m / s$
Medium
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(a)
$I_1+e=\frac{\lambda}{4}$
$I_2+e=\frac{3 \lambda}{4}$
$I_2-I_1=\frac{\lambda}{2}$
$0.48-0.15=\frac{\lambda}{2}$
$0 \lambda=0.66$
$\text { Velocity }=f \lambda=500 \times 0.66=330 \,m / s$
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