$\angle\text{BDA}$ Solution: In $\triangle\text{CAB}$ and $\triangle\text{DBA},$ AC = BD and $\angle\text{CAB} = \angle\text{DBA}$ (Given) AB (Common) Therefore, $\triangle\text{CAB}$ and $\triangle\text{DBA}$ are congruent by SAS criteria Therefore, $\angle\text{ACP} = \angle\text{BDA}$ (by CPCT)
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