Answer

  1. $\angle\text{BDA}$
    Solution:
    In $\triangle\text{CAB}$ and $\triangle\text{DBA},$
    AC = BD and $\angle\text{CAB} = \angle\text{DBA}$ (Given)
    AB (Common)
    Therefore, $\triangle\text{CAB}$ and $\triangle\text{DBA}$ are congruent by SAS criteria
    Therefore, $\angle\text{ACP} = \angle\text{BDA}$ (by CPCT)

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