Question
✓
Answer
- 57.5º
Solution:
As BC = AC, therefore triangle ABC is an isoscelestriangle.
Given $\angle\text{ACD} = 115^\circ,\ \angle\text{ACB} = 180 - 115 = 65^\circ$ (Linear Pair)
As AC = BC, therefore $\angle\text{A} =\angle\text{B}$
As sum of all the three angles of atriangle is 180º
Therefore. $\angle\text{A}+\angle\text{B} +\angle\text{ACB} = 180^\circ$
$\angle\text{A} =\angle\text{B}=57.5^\circ$
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