In the connections shown in the adjoining figure, the equivalent capacity between $A$ and $B$ will be......$\mu F$
Medium
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(d) Given circuit can be drawn as follows. It is a balance whetstone bridge type network, hence $24\, µF$ capacitor can be neglected
Equivalent capacitance between $A$ and $B$ $= 4 + 6 = 10\,µF$.
Equivalent capacitance between $A$ and $B$ $= 4 + 6 = 10\,µF$.
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