In the circuit shown below E_1, =4.0, V, R_1, = 2,Omega, E_2, = 6.0, V, R_2, = 4,Omega and R_3, = 2,Omega. The current I

Q: In the circuit shown below $E_1\, =4.0\, V$, $R_1\, = 2\,\Omega$, $E_2\, = 6.0\, V$, $R_2\, = 4\,\Omega$ and $R_3\, = 2\,\Omega$. The current $I_1$ is ............... $\mathrm{A}$

b Applying Kirchhoff's law for the loops $(1)$ and $(2)$ as shown in figure For loop $(1)$ $-2 i_{1}-2\left(i_{1}-i_{2}\right)+4=0$ $\Rightarrow 2 \mathrm{i}_{1}-\mathrm{i}_{2}=2$ .........$(i)$ For loop $(2)$ $-2\left(i_{1}-i_{2}\right)+4 i_{2}-6=0$ $\Rightarrow-\mathrm{i}_{1}+3 \mathrm{i}_{2}=3$ .........$(ii)$ On solving equation $(i)$ and $(ii),$ $\mathrm{i}_{1}=1.8 \mathrm{\,A}.$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

In the circuit shown below $E_1\, =4.0\, V$, $R_1\, = 2\,\Omega$, $E_2\, = 6.0\, V$, $R_2\, = 4\,\Omega$ and $R_3\, = 2\,\Omega$. The current $I_1$ is ............... $\mathrm{A}$

A$1.6$
B$1.8$
C$1.25$
D$1$

Diffcult

STD 11 Science
JEE
STD 12 - 3. current electricity
Physics

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