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Semiconductor Electronic: Material, Devices And Simple Circuits — Physics STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 SciencePhysicsSemiconductor Electronic: Material, Devices And Simple Circuits1 Mark
MCQ
In the circuit shown in Fig., if the diode forward voltage drop is 0.3V, the voltage difference between A and B is:

  • A
    1.3V.
  • B
    2.3V.
  • C
    0.
  • D
    0.5V.
✓

Answer

  1. 2.3V.

Solution:

If V is the potential difference between A and B, then according to the questions and using Kirchhoff’s law, we have

V - 0.3 = [(5+ 5)103] × (0.2 × 1(10-3))

⇒ V - 0.3 = [(5 + 5)103] × (0.2 × 10-3)

⇒ V - 0.3 = 10 × 103 × 0.2 × 10-3 = 2

⇒ V = 2 + 0.3 = 2.3V

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