In the circuit shown in figure, the power which is dissipated as heat in the $6\,\Omega $ resistor is $6\,W$. What is the value of resistance $R$ in the circuit? ................ $\Omega$
Medium
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Current in $6\, \Omega \quad \mathrm{I}=\sqrt{\frac{\mathrm{P}}{\mathrm{R}}}=\sqrt{\frac{6}{6}}=1$
${\mathrm{I}=\frac{12}{6+\frac{8 \mathrm{P}}{8+\mathrm{R}}}} $
${1=\frac{12}{48+14 \mathrm{R}}(8+\mathrm{R})}$
${\mathrm{R}=24\, \Omega}$
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