MCQ
In the equilibrium $AB$ $\rightleftharpoons$ $A + B$; if the equilibrium concentration of $A$ is doubled, the equilibrium concentration of $B$ would become:
- ATwice
- ✓Half
- C$1/4^{th}$
- D$1/8^{th}$
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$2MnO_4^ - + 5{C_2}O_4^ - + 16{H^ + } \to 2M{n^{ + + }} + 10C{O_2} + 8{H_2}O$
Here $20\, mL$ of $0.1\, M\, KMnO_4$ is equivalent to

$(I)$ As wavelength decreases, the lines in the series converge
$(II)$ The integer $n_{1}$ is equal to $2$
$(III)$ The lines of longest wavelength corresponds to $\mathrm{n}_{2}=3$
$(IV)$ The ionization energy of hydrogen can be calculated from wave number of these lines