Question
In the figure $\text{ABCD}$ is a parallelogram, $\text{CE}$ bisects $\angle\text{C}$ and $\text{AF}$ bisects $\angle\text{A}$. In each of the following, if the statement is true, give a reason for the same.
$i. \angle\text{A}=\angle\text{C}$
$ii. \angle\text{FAB}=\frac{1}{2}\angle\text{A}$
$iii.\angle\text{DCE}=\frac{1}{2}\angle\text{C}$
$iv. \angle\text{CEB}=\angle\text{FAB}$
$v. \text{CE}\parallel\text{AF}$
$i. \angle\text{A}=\angle\text{C}$
$ii. \angle\text{FAB}=\frac{1}{2}\angle\text{A}$
$iii.\angle\text{DCE}=\frac{1}{2}\angle\text{C}$
$iv. \angle\text{CEB}=\angle\text{FAB}$
$v. \text{CE}\parallel\text{AF}$
