In the figure shown, amount of heat supplied to one mole of an ideal gas is plotted on the horizontal axis and amount of work done by gas is drawn on vertical axis. Assuming process be isobaric i.e. gas can be
Medium
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$\frac{W}{Q}=\frac{n R \Delta T}{n C_{p} \Delta T}=\frac{3 2}{80}=\frac{2}{5}$
$5 \mathrm{R}=2 \mathrm{C}_{\mathrm{p}}=2\left[\mathrm{C}_{\mathrm{v}}+\mathrm{R}\right]$
$C_{v}=\frac{3 R}{2}$
$\therefore(1)$
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