A system is provided with $200 \,cal$ of heat and the work done by the system on the surrounding is $40 \,J$. Then its internal energy
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(c) $\Delta Q = \Delta U + \Delta W$
$\Delta Q = 200cal = 200 \times 4.2 = 840J$ and $\Delta W = 40J$
==>$\Delta U = \Delta Q - \Delta W = 840 - 40 = 800J$
$\Delta Q = 200cal = 200 \times 4.2 = 840J$ and $\Delta W = 40J$
==>$\Delta U = \Delta Q - \Delta W = 840 - 40 = 800J$
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