In the cyclic process shown in the figure, the work done by the gas in one cycle is
A$28\,{P_1}{V_1}$
B$14\,{P_1}{V_1}$
C$18\,{P_1}{V_1}$
D$9\,{P_1}{V_1}$
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D$9\,{P_1}{V_1}$
d (d) Work done = Area under curve $ = \frac{{6{P_1} \times 3{V_1}}}{2}= 9 P_1V_1$
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