In the following diagram, the lengths of wires $A B$ and $B C$ are equal, but the radius of wire $A B$ is double that of $B C$. The ratio of potential gradient on wires $A B$ and on $B C$ will be (wires are made of same material)
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(b)
$=\frac{R}{4}$
$i=\frac{4 E}{5 R}$
$\Delta V_1=\frac{E}{5}$
$\Delta V_2=\frac{4 E}{5}$
$\Delta V_1=\Delta V_2$
$=1: 4$
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