Four resistances are connected in a circuit in the given figure. The electric current flowing through $4\, ohm$ and $6\, ohm$ resistance is respectively
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Equivalent resistance $ = \frac{{4 \times 4}}{{4 + 4}} + \frac{{6 \times 6}}{{6 + 6}} = 5\,ohm$
So the current in the circuit $ = \frac{{20}}{5} = 4\,ampere$
Hence the current flowing through each resistance $= 2\,ampere$.
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