Question
In the given circle with diameter AB, find the value of x.
✓
Answer
∠ ABD = ∠ ACD = 30°...(∠s of same segment)
∠ADB = 90°....(∠ in the semi circle)
In ΔADB,
x° + 90° + 30° = 180°....(Sum of all ∠s of triangle)
x° = 180° - 120°
x° = 60°.
∠ADB = 90°....(∠ in the semi circle)
In ΔADB,
x° + 90° + 30° = 180°....(Sum of all ∠s of triangle)
x° = 180° - 120°
x° = 60°.
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