In the given circuit, the potential difference across the inductor L and resistor R are 200V and 150V respectively and the rms. value of current is 5A. Calculate (i) the impedance of the circuit and (ii) the phase angle between the voltage and the current.
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Voltage applied $\text{V}=\sqrt{\text{V}^2_\text{L}+\text{V}^2_\text{R}}=\sqrt{(200)^2+(150^2)}=250\text{V}$Impedance of circuit, $\text{Z}=\frac{\text{V}}{\text{I}}=\frac{250}{5}=50\Omega$
Phase angle between voltage and current
$\tan\varphi=\frac{\text{x}_{\text{L}}}{\text{R}}=\frac{\text{V}_{\text{L}}}{\text{V}_{\text{R}}}=\frac{200}{150}=\frac{4}{3}$
$\varphi=\tan^{-1}\Big(\frac{4}{3}\Big)=53^{\circ}$
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