MCQ
In the given circuit calculate potential difference between $A$ and $B$ ............... $\mathrm{V}$
  • A
    $-5.8$
  • B
    $-4.6$
  • C
    $-5.8$
  • $-5.2$

Answer

Correct option: D.
$-5.2$
d
$\mathrm{K.V}$ $\mathrm{.L.}$ on left mesh

${2-3 \mathrm{I}_{1}-2 \mathrm{I}_{1}=0} $

${\mathrm{I}_{1}=0.4 \mathrm{\,amp}}$

$\mathrm{K.V.L.}$ on right mesh

$4-3 I_{2}-5 I_{2}=0$

$\mathrm{I}_{2}=0.5 \mathrm{\,amp}$

Potential difference between $A $ and $ B$

${\mathrm{V}_{\mathrm{A}}+3 \mathrm{I}_{1}+4=\mathrm{V}_{\mathrm{B}}} $

${\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=-3(\mathrm{O} .4)-4=-5.2 \mathrm{\,V}}$

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