ICSE BoardEnglish MediumSTD 10MathematicsCircles2 Marks
Question
In the given figure, AB = BC = CD and ∠ABC = 132° . Calcualte: ∠AED
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Answer
In the figure, O is the centre of circle, with AB = BC = CD. Also, ∠ABC = 132° Similarly, AB = BC = CD ∠AEB = ∠BEC = ∠CED = 24° ∠AED = ∠AEB + ∠BEC + ∠CED = 24° + 24° + 24°= 72°
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