MCQ
In the given figure, $\text{ABCD}$ is a $\|  \mathrm{gm}$ in which $A B=C D=5 \mathrm{\sim cm}$ and $B D \perp D C$ such that $B D=6.8 \mathrm{\sim cm}$. Then, the area of $\mathrm{ABCD}=$ ?
  • A
    $17 \mathrm{\sim cm}^2$
  • B
    $25 \mathrm{\sim cm}^2$
  • $34 \mathrm{\sim cm}^2$
  • D
    $68 \mathrm{\sim cm}^2$

Answer

Correct option: C.
$34 \mathrm{\sim cm}^2$
Since $\text{ABCD}$ is a $\|\mathrm{gm}, A B\| C D$.
$\operatorname{ar}(\| g m \mathrm{ABCD})=$ base $\times$ height
$=A B \times B D$
$=5 \times 6.8$
$=34 \mathrm{\sim cm}^2$

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