MCQ
The decimal form of $\frac{\text{1}}{999}$ is:
- A$0.0\overline{01}$
- ✓$0.\overline{001}$
- C$0.999$
- D$0.00\overline{1}$
✓
Answer
Correct option: B.
$0.\overline{001}$
When we divide $1$ by $999$ result is $0.001001001001001.....$
So, $0.\overline{001}=\frac{1}{999}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following numbers can be represented as non$-$terminating, repeating decimals?
→If $f(x) = x^2 - 5x + 1$, that the value of $f(2) + f(-1)$ is:
→The equal sides of the isosceles triangle are $12\ cm,$ and the perimeter is $30\ cm.$ The area of this triangle is:
→If $a + b + c = 0$, then $\frac{\text{a}^2}{\text{bc}}+\frac{\text{b}^2}{\text{ca}}+\frac{\text{c}^2}{\text{ab}}=$
→Write the correct answer in the following: In coordinates of $P$ are:
→In $\triangle A B C$ and $\triangle D E F$ its is given that $\angle B=\angle E$ and $\angle C=\angle F$ in order that $\triangle A B C \cong \triangle D E F$ we must have
→$\sqrt{3}$ is a polynomial of degree
→The zeros of the polynomial $p(x)=2 x^2+7 x-4$ are:
→$ABCD$ is a parallelogram, $M$ is the mid-point of $BD$ and $BM$ bisects $\angle\text{B}.$ Then, $\angle\text{AMB}=$
→The value of $\frac{(0.013)^3+(0.007)^3}{(0.013)^2-0.013\times0.007+(0.007)^2},$ is:
→