In simple harmonic motion, the ratio of acceleration of the particle to its displacement at any time is a measure of
Easy
Download our app for free and get started
(c) $a = - {\omega ^2}x$
==> $\left| {\frac{a}{x}} \right| = {\omega ^2}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A body of mass $5\, gm$ is executing $S.H.M.$ about a point with amplitude $10 \,cm$. Its maximum velocity is $100\, cm/sec$. Its velocity will be $50\, cm/sec$ at a distanceView Solution
- 2A wooden cube (density of wood $'d'$ ) of side $'l'$ floats in a liquid of density $'\rho '$ with its upper and lower surfaces horizontal. If the cube is pushed slightly down and released, it performs simple harmonic motion of period $'T'$. Then, $'T'$ is equal toView Solution
- 3A person of mass $M$ is, sitting on a swing of length $L$ and swinging with an angular amplitude $\theta_0$. If the person stands up when the swing passes through its lowest point, the work done by him, assuming that his centre of mass moves by a distance $l\, ( l < < L)$, is close toView Solution
- 4View SolutionIf the metal bob of a simple pendulum is replaced by a wooden bob, then its time period will
- 5The displacement equations of two interfering waves are given byView Solution
$y_1 =10 \sin \left(\omega t+\frac{\pi}{3}\right) cm$
$y_2 =5[\sin (\omega t)+\sqrt{3} \cos \omega t] \;cm$ respectively.
The amplitude of the resultant wave is $.............cm$.
- 6A mass $m =100\, gms$ is attached at the end of a light spring which oscillates on a frictionless horizontal table with an amplitude equal to $0.16$ metre and time period equal to $2 \,sec$. Initially the mass is released from rest at $t = 0$ and displacement $x = - 0.16$ metre. The expression for the displacement of the mass at any time $t$ isView Solution
- 7The period of oscillation of a mass $M$ suspended from a spring of negligible mass is $T$. If along with it another mass $M$ is also suspended, the period of oscillation will now beView Solution
- 8On a planet a freely falling body takes $2 \,sec$ when it is dropped from a height of $8 \,m$, the time period of simple pendulum of length $1\, m$ on that planet is ..... $\sec$View Solution
- 9The period of oscillation of a simple pendulum of constant length at earth surface is $T$. Its period inside a mine isView Solution
- 10An object of mass $0.2\, kg$ executes simple harmonic along $X-$ axis with frequency of $\frac{{25}}{\pi }Hz$. At the position $x = 0.04m$, the object has kinetic energy of $0.5 \,J$ and potential energy of $0.4\, J$ amplitude of oscillation in meter is equal toView Solution