In the given figure $R_1=10 \Omega, R_2=8 \Omega, R_3=4 \Omega$ and $R_4=8 \Omega$. Battery is ideal with emf $12 \mathrm{~V}$. Equivalent resistant of the circuit and current supplied by battery are respectively.
JEE MAIN 2024, Diffcult
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Here $R_2, R_3, R_4$ are in parallel
$\frac{1}{\mathrm{R}_{254}}=\frac{1}{\mathrm{R}_2}+\frac{1}{\mathrm{R}_5}+\frac{1}{\mathrm{R}_4}$
$\mathrm{R}_{254}=2 \Omega$
$R_{234}$ is in series with $R_1$ so
$\mathrm{R}_{\mathrm{eq}}=\mathrm{R}_{234}+\mathrm{R}_1=2+10=12 \Omega$
$\mathrm{i}=\frac{12}{12}=1 \mathrm{Amp}$
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