MCQ
In the given figure, the current amplitude is
- ✓$\sqrt {\frac{{5V_0^2}}{{4\left( {{\omega ^2}{L^2} + {R^2}} \right)}}} $
- B$\frac{{{v_0}}}{{\sqrt {4\left( {{\omega ^2}{L^2} + {R^2}} \right)} }}$
- C$\frac{{\sqrt 5 {v_0}}}{{2\sqrt {{\omega ^2}{L^2} - {R^2}} }}$
- D$\frac{{\sqrt 5 {v_0}}}{{2\sqrt {{R^2} - {\omega ^2}{L^2}} }}$