In the given figure, the emf of the cell is 2.2, {V} and if internal resistance is 0.6, Omega. Calculate the power dissipated in the

Q: In the given figure, the $emf$ of the cell is $2.2\, {V}$ and if internal resistance is $0.6\, \Omega$. Calculate the power dissipated in the whole circuit: (in $W$)

c $\frac{1}{R_{e q}}=\frac{1}{4}+\frac{1}{8}+\frac{1}{12}+\frac{1}{6}=\frac{6+3+2+4}{24}=\frac{15}{24}$ $R_{e q}=\frac{24}{15}=1.6 \Rightarrow R_{T}=1.6+0.6=2.2 \,\Omega$ $P=\frac{V^{2}}{R_{T}}=\frac{(2.2)^{2}}{2.2}=2.2 \,{W}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

In the given figure, the $emf$ of the cell is $2.2\, {V}$ and if internal resistance is $0.6\, \Omega$. Calculate the power dissipated in the whole circuit: (in $W$)

A$1.32$
B$0.65$
C$2.2$
D$4.4$

JEE MAIN 2021, Diffcult

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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