MCQ
In the given figure, what will be the coefficient of mutual inductance?
Image
  • A
    $\frac{\mu_0 a}{2 \pi} \ln \left(1+\frac{a}{2 b}\right)$
  • B
    $\frac{\mu_0 a }{\pi} \ln \left(1+\frac{ b }{2 a }\right)$
  • $\frac{\mu_0 a}{2 \pi} \ln \left(1+\frac{a}{b}\right)$
  • D
    $\frac{\mu_0 a}{2 \pi} \ln \left(1+\frac{b}{a}\right)$

Answer

Correct option: C.
$\frac{\mu_0 a}{2 \pi} \ln \left(1+\frac{a}{b}\right)$
(C) $\frac{\mu_0 a}{2 \pi} \ln \left(1+\frac{a}{b}\right)$
Magnetic field due to wire,
$
\begin{array}{l}
\qquad B=\frac{\mu_0}{2 \pi x} \cdot i \\
d A=a d x \\
\text { and } \quad d \phi=B \cdot d A \\
\int d \phi=\int B d A \\
\phi=\frac{\mu_0 i}{2 \pi} \int_b^{a+b} \frac{a \cdot d x}{x} \\
\phi=\frac{\mu_0 i}{2 \pi} a \ln [x]_b^{a+b}=\frac{\mu_0 i}{2 \pi} a[\ln (a+b)-\ln b] \\
=\frac{\mu_0 i}{2 \pi} a\left[\ln \left(1+\frac{a}{b}\right)\right]=M i
\end{array}
$
where, $M =$ coefficient of mutual inductance.
$
M=\frac{\mu_0 a}{2 \pi} \ln \left(1+\frac{a}{b}\right)
$

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