In the reaction A_ (g) + 2B_ (g) C_ (g) + Q ,kJ, greater product … - Vidyadip

MCQ

In the reaction $A_{(g)} + 2B_{(g)}$ $\rightleftharpoons$ $C_{(g)} + Q\,kJ$, greater product will be obtained or the forward reaction is favoured by

A
At high temperature and high pressure
B
At high temperature and low pressure
✓
At low temperature and high pressure
D
At low temperature and low pressure

✓

Answer

Correct option: C.

At low temperature and high pressure

(c) Both $\Delta n$ and $\Delta H$ are negative. Hence, high pressure and low temperature will forward reaction.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 6.1. Equilibrium - 1 (chemical Equilibrium)→6.1. Equilibrium - 1 (chemical Equilibrium) — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

For the reaction ${N_2}\left( g \right) + {O_2}\left( g \right) \rightleftharpoons 2NO\left( g \right)\,;\,{K_C} = 2$ then degree of dissociation of $O_2$ is

Assertion : $Al(OH)_3$ is insoluble in $NH_4OH$ but soluble in $NaOH$ .

Reason : $NaOH$ is strong alkali.

Benzene is obtained from

Which of the following best describes the diagram of molecular orbital?

According to law of photochemical equivalence the energy absorbed (in ergs/mole) is given as $(h = 6.62 \times 10^{-27} \ ergs,$$ \ c = 3 \times cm s^{-1}, $$\ N_A = 6.02 \times 10^{-23} \ mol^{-1})$

Which of the following is responsible to rule out the existence of definite paths or trajectories of electrons?

In the given reaction, the product $P$ is

The $IUPAC$ name of the following compound is $\mathop {\mathop {C{H_3} - CH - C{H_2}C{H_2}C{H_3}}\limits_{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} }\limits_{CH{{(C{H_3})}_2}\,\,\,\,} $

In the following reaction:

$HC \equiv CH\,\xrightarrow[{H{g^{2 + }}}]{{{H_2}S{O_4}}}\,'P'$

Product $'P'$ will not give

Correct lewis structure is