In the reaction of hypobromite with amide, the carbonyl carbon is lost as :
JEE MAIN 2021, Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionThe order of basicity of amines in gaseous state is
- 2${C_2}{H_5}Br\,\xrightarrow{{AgCN}}X\xrightarrow[{Zn - Hg/HCl}]{{{\text{Reduction}}}}Y,$ Here $Y$ isView Solution
- 3Match the reactions in Column $I$ with appropriate options in Column $II$.View Solution
Column $I$ Column $II$ $(A)$ $Image$ $(p)$ Racemic mixture $(B)$ $Image$ $(q)$ Addition reaction $(C)$ $Image$ $(r)$ Substitution reaction $(D)$ $Image$ $(s)$ Coupling reaction $(t)$ Carbocation intermediate 
- 4Which of the following alkene cannot be prepared by de-amination of $n-Bu- NH_2$ with $NaNO_2/HCl$ ?View Solution
- 5What is the product obtained in the following reactionView Solution
(image) $\xrightarrow[{N{H_4}Cl}]{{Zn}}.....?$
- 6Benzamide on reaction with $POC{l_3}$ givesView Solution
- 7Identify product $D$ in the following reaction sequenceView Solution
$\begin{matrix}
\begin{matrix}
\,\,\,\,\,C{{H}_{3}} \\
| \\
\end{matrix}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}-C-C{{H}_{2}}C{{H}_{2}}OH \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
\end{matrix}$ $\xrightarrow[{{H_2}O,heat}]{{{K_2}C{r_2}{O_7};{H_2}S{O_4}}}A$ $\xrightarrow{{SOC{l_2}}}B\xrightarrow[{(2{\kern 1pt} mole)}]{{{{(C{H_3})}_2}NH}}C$ $\xrightarrow[{2.{\kern 1pt} {H_2}O}]{{\begin{array}{*{20}{c}}
{1.{\kern 1pt} LiAl{H_4}} \\
{diethyl{\kern 1pt} {\kern 1pt} ether}
\end{array}}}D$ - 8Given below are two statements :View Solution
Statement $I$: Aniline reacts with con. $\mathrm{H}_2 \mathrm{SO}_4$ followed by heating at $453-473 \mathrm{~K}$ gives $\mathrm{p}$ aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.
Statement $II$: In Friedel - Craft's alkylation and acylation reactions, aniline forms salt with the $\mathrm{AlCl}_3$ catalyst. Due to this, nitrogen of aniline aquires a positive charge and acts as deactivating group.
In the light of the above statements, choose the correct answer from the options given below :
- 9View SolutionMethod by which aniline cannot be prepared is
- 10Reaction of propanamide with $Br _2 / KOH$ (aq) produces :View Solution