MCQ
In the relation:
$y=a \sin (\omega t-K x)$,
the dimensional formula for K is:
  • A
    $\left[ M ^0 L^{-1} T^{-1}\right]$
  • B
    $\left[ M ^0 LT \right]$
  • C
    $\left[ M ^0 L^{-1} T^0\right]$
  • D
    $\left[ M ^0 LT ^{-1}\right]$

Answer

C.$\left[ M ^0 L^{-1} T^0\right]$
Explanation:Here, Kx is dimensionless. Hence,
$[K]=\left[\frac{1}{x}\right]=\left[M^0 L^{-1} T^0\right]$

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