Two long parallel copper wires carry currents of $5\,A$ each in opposite directions. If the wires are separated by a distance of $0.5\,m$, then the force between the two wires is
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(b) $F = {10^{ - 7}}\frac{{2{i_1}{i_2}}}{a} = {10^{ - 7}} \times \frac{{2 \times 5 \times 5}}{{0.5}} = {10^{ - 5}}\,N$ (repulsive)
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