In the wave equation $y =0.5 \sin \frac{2 \pi}{\lambda}(400 t - x )\,m$ the velocity of the wave will be ......... $m / s$
JEE MAIN 2022, Easy
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$y =0.5 \sin \left(\frac{2 \pi}{\lambda} 400 t -\frac{2 \pi}{\lambda} x \right)$
$\omega=\frac{2 \pi}{\lambda} 400$
$K =\frac{2 \pi}{\lambda}$
$v =\frac{\omega}{ k } \quad[ v =400\,m / s ]$
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