In the Young's arrangement, screen starts moving towards right wi… - Vidyadip

MCQ

In the Young's arrangement, screen starts moving towards right with constant speed $v$. Initial distance between screen and plane of slits is $x$. At $t=0$, 1st order maxima is lying at point A. After how much time first order minima lies at point $A$ ?

A
$\frac{x}{2 v}$
✓
$\frac{x}{v}$
C
$\frac{x}{3 v}$
D
$\frac{2 x}{3 v}$

✓

Answer

Correct option: B.

$\frac{x}{v}$

b
(b)

Distance of $1^{\text {st }}$ maxima from central fringe $=\frac{\lambda D}{d} \quad[D=x]$

Distance of 1 st minima $=\frac{\lambda D}{2 d}$

$D$ at time $t=D_t=x+V t$

$\frac{\lambda x}{d}=\frac{\lambda(x+V t)}{2 d}$

$x=V t$

or $\quad t=\frac{x}{V}$

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