Maharashtra BoardEnglish MediumSTD 10MathsQuestion Bank - P23 Marks
Question
In $\triangle A B C, \cos C=\frac{12}{13}$ and $B C=24$, then $A C=$ ?
✓
Answer
$\cos C=\frac{12}{13}$ .....(i) [Given] In $\triangle ABC$, Let $\angle A B C=90^{\circ}$ $\therefore \cos C =\frac{ BC }{ AC } \quad \ldots .$. (ii) [By definition] $\therefore \frac{ BC }{ AC }=\frac{12}{13} \ldots \ldots[$ From (i) and (ii) $]$ $\therefore \frac{24}{ AC }=\frac{12}{13}$ $\therefore \frac{24 \times 13}{12}= AC$ $\therefore \frac{312}{12}= AC$ $\therefore AC =26$ units
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