Question
ind the value of $\text{cot}\text{(tan}^1\text{a}+\text{cot}^1\text{a}).$
  1. 0
  2. −1
  3. 2
  4. 1

Answer

  1. 0
Solution:
 
We know,
$\text{tan}^1\text{a}+\text{cot}^{-1}\text{a}=\frac{\pi}{2}$
Therefore,
$\text{cot}(\text{tan}^{−1}\text{a}+\text{cot}^{−1}a)=\text{cot}\frac{\pi}{2}=0$

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