MCQ
ind the value of $\text{cot}\text{(tan}^1\text{a}+\text{cot}^1\text{a}).$
 
  • 0
  • B
    −1
  • C
    2
  • D
    1

Answer

Correct option: A.
0
We know,

$\text{tan}^1\text{a}+\text{cot}^{-1}\text{a}=\frac{\pi}{2}$

Therefore,

$\text{cot}(\text{tan}^{−1}\text{a}+\text{cot}^{−1}a)=\text{cot}\frac{\pi}{2}=0$

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