Question
Insert three rational number between:$-3$ and $3$
✓
Answer
A rational number lying between $- 3$ and $3$
$=\frac{-3+3}{2} $
$=\frac{0}{2} $
$=0$
A rational number lying between $-3$ and $0$
$=\frac{-3+0}{3^2} $
$=-\frac{3^2}{2}$
A rational number lying between $0$ and $3$
$=\frac{0+3}{2} $
$=\frac{3}{2} $
$-3<-\frac{3}{2}<0<\frac{3}{2}<3$
Hence, three rational numbers between $-3$ and $3$ are $-\frac{3}{2}, 0$ and $\frac{3}{2}$.
$=\frac{-3+3}{2} $
$=\frac{0}{2} $
$=0$
A rational number lying between $-3$ and $0$
$=\frac{-3+0}{3^2} $
$=-\frac{3^2}{2}$
A rational number lying between $0$ and $3$
$=\frac{0+3}{2} $
$=\frac{3}{2} $
$-3<-\frac{3}{2}<0<\frac{3}{2}<3$
Hence, three rational numbers between $-3$ and $3$ are $-\frac{3}{2}, 0$ and $\frac{3}{2}$.
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