Download App

STD 12 - 7.1 inderfinite integral — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 7.1 inderfinite integral1 Mark
MCQ
$\int_{}^{} {\frac{{1 + {{\cos }^2}x}}{{{{\sin }^2}x}}dx} = $
  • A
    $ - \cot x - 2x + c$
  • B
    $ - 2\cot x - 2x + c$
  • ✓
    $ - 2\cot x - x + c$
  • D
    $ - 2\cot x + x + c$
✓

Answer

Correct option: C.
$ - 2\cot x - x + c$
c
(c) $\int_{}^{} {\frac{{1 + {{\cos }^2}x}}{{{{\sin }^2}x}}} \,dx = \int_{}^{} {({\rm{cose}}{{\rm{c}}^2}x + {{\cot }^2}x)\,dx} $
$ = \int_{}^{} {(2{\rm{cose}}{{\rm{c}}^2}x - 1)\,dx = - 2\cot x - x + c.} $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 7.1 inderfinite integral→STD 12 - 7.1 inderfinite integral — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

If $f(x) = |x - 2|$, then
→
For each real number $x$, let $[ x ]$ denote the greatest integer less than or equal to $x$, and let $\{ x \}= x -[ x ]$. Then the smallest positive integer $M$ for which $\int_1^M\{x\}^{[x]} d x > 1$ is
→
Solve $|x\,-\,2| + |x\,-\,1| = x\,-\,3$
→
The integral $\int {\frac{{dx}}{{{{(x + 1)}^{\frac{3}{4}}}{{(x - 2)}^{\frac{5}{4}}}}}} $ is equal to
→
Curve passing through $(3, 0)$ and satisfying the differential equation $\left( {9 - {x^2}} \right){\left( {\frac{{dy}}{{dx}}} \right)^2} = 9 - {y^2}$ represents
→
$\text{f}(\text{x})=\sin +\sqrt{3}\cos\text{x}$ is maximum when x =
→
$\sin\big[\cot^{-1}\big\{\tan\big(\cos^{-1}\text{x}\big)\big\}\big]$ is equal to:
→
Let $X_n=\{1,2,3, \ldots, n\}$ and let a subset $A$ of $X_n$ be chosen so that every pair of elements of $A$ differ by at least 3. (For example, if $n=5, A$ can be $\phi,\{2\}$ or $\{1,5\}$ among others). When $n=10$, let the probability that $1 \in A$ be $p$ and let the probability that $2 \in A$ be Then,
→
By graphical method, the solution of linear programming problem
Maximize $Z = 3x_1 + 5x_2$
Subject to
$3x_1 + 2x_2 \leq 18$
$x_1 \leq 4$
$x_2 \leq 6$
$x1 \geq 0, x2 \geq 0$, is:
→
If the matrices $A=\left[\begin{array}{ccc}{1} & {1} & {2} \\ {1} & {3} & {4} \\ {1} & {-1} & {3}\end{array}\right], B=\operatorname{adj} A$ and $\mathrm{C}=3 \mathrm{A},$ then $\frac{|\mathrm{adjB}|}{|\mathrm{C}|}$ is equal to
→