(1+ x)^2 x d x= - Vidyadip

MCQ

$\int \frac{(1+\log x)^2}{x} d x=$

✓
$\frac{1}{3}(1+\log x)^3+C$
B
$\frac{1}{2}(1+\log x)^2+C$
C
$\log \{\log (1+x)\}+C$
D
इनमें से कोई नहीं

✓

Answer

Correct option: A.

$\frac{1}{3}(1+\log x)^3+C$

A

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from समाकलन→समाकलन — all question types→गणित कक्षा 12 साइन्स question papers→CBSE Board कक्षा 12 साइन्स question papers→CBSE Board question paper generator→

Similar questions

फलन $f(x)=x-\frac{1}{x}$ है-

$\frac{d}{d x}(\cos x)=$

यदि $y=\sqrt{\sin x+\sqrt{\sin x+\sqrt{\sin x+\ldots \infty}}}$ तो $\frac{d y}{d x}=$

यदि $A=\left[\begin{array}{cc}2 & -1 \\ 1 & 3\end{array}\right]$ तो $A^{-1}=$

$\operatorname{Lim}_{n \rightarrow \infty} \sum_{r=1}^n \frac{r^3}{r^4+n^4}$ का मान है :

माना कि $A$ और $B$ दो घटनाएँ हैं ताकि $P(A)=\frac{1}{3}, P(B)=\frac{1}{4}$ and $P(A \cap B)=\frac{1}{5}$ then $P(A / B)=$

$\left[\begin{array}{ll}2 & 3 \\ 5 & 7\end{array}\right]\left[\begin{array}{l}1 \\ 1\end{array}\right]=$

$\int\left(\sin ^{-1} x+\cos ^{-1} x\right) d x=$

यदि $\tan ^{-1}\left(\frac{a}{x}\right)+\tan ^{-1}\left(\frac{b}{x}\right)=\frac{\pi}{2}$, तब x =

रेखाएँ $\frac{x-1}{1}=\frac{y-2}{2}=\frac{z-3}{3}$ तथा $\frac{x}{2}=\frac{y+2}{2}=\frac{z-3}{-2}$ परस्पर हैं :