_ ^ cose c ^2 x ;dx is equal to - Vidyadip

MCQ

$\int_{}^{} {{\rm{cose}}{{\rm{c}}^2}x\;dx} $ is equal to

A
$\cot x + c$
✓
$ - \cot x + c$
C
${\tan ^2}x + c$
D
$ - {\cot ^2}x + c$

✓

Answer

Correct option: B.

$ - \cot x + c$

b
(b)$\int_{}^{} {{\rm{cose}}{{\rm{c}}^{\rm{2}}}x\,dx} = - \cot x + c$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from STD 12 - 7.1 inderfinite integral→STD 12 - 7.1 inderfinite integral — all question types→Mathematics STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

Let $S=(0,1) \cup(1,2) \cup(3,4)$ and $T=\{0,1,2,3\}$. Then which of the following statements is(are) true ?

($A$) There are infinitely many functions from $S$ to $T$

($B$) There are infinitely many strictly increasing functions from $\mathrm{S}$ to $\mathrm{T}$

($C$) The number of continuous functions from $\mathrm{S}$ to $\mathrm{T}$ is at most $120$

($D$) Every continuous function from $\mathrm{S}$ to $\mathrm{T}$ is differentiable

Let $\vec{a}=\hat{i}+\hat{j}+\hat{k}, \vec{b}=\hat{i}-\hat{j}+\hat{k}$ and $\vec{c}=\hat{i}-\hat{j}-\hat{k}$ be three vectors. A vector $\vec{v}$ in the plane of $\vec{a}$ and $\vec{b}$, whose projection on $\vec{c}$ is $\frac{1}{\sqrt{3}}$, is given by

Choose the correct answer from the given four options : The function $\text{f(x)}=4\sin^3\text{x}-6\sin^2\text{x}+12\sin\text{x}+100$ is strictly :

The element in the first row and third column of the inverse of the matrix $\left[ {\begin{array}{*{20}{c}}1&2&{ - 3}\\0&1&2\\0&0&1\end{array}} \right]$ is

If $\int\frac{\cos8\text{x}+1}{\tan2\text{x}-\cot2\text{x}}\text{ dx}=\text{a}\cos8\text{x}+\text{C},$ then $a =$

The value of $c$ in Rolle's theorem for the function $\text{f}(\text{x})=\frac{\text{x}(\text{x}+1)}{\text{e}^{\text{x}}}$ defined on $[-1, 0]$ is:

Let $y=f(x)=\sin ^3\left(\frac{\pi}{3}\left(\cos \left(\frac{\pi}{3 \sqrt{2}}\left(-4 x^3+5 x^2+1\right)^{\frac{3}{2}}\right)\right)\right)$ .Then, at $x =1$,

The set of points of discontinuity of the function $f(x)$ = $\frac{{\tan \,x.{{\tan }^{ - 1}}\left( {\frac{1}{{x - 1}}} \right)}}{{x\left( {x - 3} \right)\left( {x - 5} \right)}}$ is

The value of $\int {\frac{{{e^x}\, + \,9\,\cos \,x\, - \,2\,\sin \,x\, + \,7}}{{{e^x}\, + \,7\,\sin \,x\, + \,11\,\cos \,x\, + \,14}}\,dx} $ is

(where $C$ is constant of integration)

$\int_0^{1/2} {\frac{{x{{\sin }^{ - 1}}x}}{{\sqrt {1 - {x^2}} }}\,dx = } $