MCQ
$\int_{}^{} {{{\tan }^2}x\;dx} $ is equal to
- A$\tan x + x + c$
- ✓$\tan x - x + c$
- C$\sec x + x + c$
- D$\sec x - x + c$
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$\left( {{{\partial u} \over {\partial x}} + {{\partial u} \over {\partial y}} + {{\partial u} \over {\partial z}}} \right)$ $(x + y + z) =$