MCQ
$\int {{x^3}\log x\,\,dx = } $
  • A
    $\frac{{{x^4}\log x}}{4} + c$
  • $\frac{1}{{16}}[4{x^4}\log x - {x^4}] + c$
  • C
    $\frac{1}{8}[{x^4}\log x - 4{x^2}] + c$
  • D
    $\frac{1}{{16}}[4{x^4}\log x + {x^4}] + c$

Answer

Correct option: B.
$\frac{1}{{16}}[4{x^4}\log x - {x^4}] + c$
(b) $I = \int {{x^3}\log x\,dx} $$ = \frac{{{x^4}}}{4}\log x - \int {\frac{{{x^4}}}{4}\frac{1}{x}dx + c} $
$ = \frac{{{x^4}}}{4}\log x - \int {\frac{{{x^3}}}{4}dx\, = \,\frac{{{x^4}}}{4}\log x - \frac{{{x^4}}}{{16}} + c} $
$ = \frac{1}{{16}}[4{x^4}\log x - {x^4}] + c$.

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