MCQ
$\int_0^{\pi /2} {\frac{{dx}}{{1 + {{\tan }^3}x}}} = $
- A$0$
- B$1$
- C$\frac{\pi }{2}$
- ✓$\frac{\pi }{4}$
$ = \int_0^{\pi /2} {\frac{{{{\sin }^3}x}}{{{{\cos }^3}x + {{\sin }^3}x}}dx} $ .....$(ii)$
Adding $(i)$ and $(ii),$ we get
$2I = \int_0^{\pi /2} {dx \Rightarrow I = \frac{\pi }{4}.} $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.