MCQ
$\int_0^{\pi /2} {\frac{{x + \sin x}}{{1 + \cos x}}\,dx = } $
- A$ - \log 2$
- B$\log 2$
- ✓$\frac{\pi }{2}$
- D$0$
$ = \frac{1}{2}\int_0^{\pi /2} {x{{\sec }^2}\frac{x}{2}} dx + \int_0^{\pi /2} {\tan \frac{x}{2}dx} $.
$ = \left| {\,x\tan \frac{x}{2}\,} \right|_0^{\pi /2} = \frac{\pi }{2}\tan \frac{\pi }{4} = \frac{\pi }{2}$.
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