Question
$\int_1^2 x^2 d x$

Answer

$
\begin{aligned}
\int_1^2 x^2 d x & =\left[\frac{x^3}{3}\right]_1^2 \\
& =\frac{1}{3}(8-1)=\frac{7}{3} .
\end{aligned}
$

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