Question
It is given that the length of the rectangular piece is $20\ m$ and its width is $15\ m$.And, from each corner a quadrant each of radius $3.5\ m$ has been cut out. A rough figure for this is given below:
✓
Answer
Length of rectangular portion $(l) = 20m$
breadth $(b) = 15m$
Area of the rectangular piece $= l \times b = 20 \times 15 = 300m^2$
Radius of semicircular portion $(r) = 3.5m$
Total area of $4$ quadrants
$=4\times\frac{1}{4}\times\pi\text{r}^2=\frac{22}{7}\times(3.5)^2\text{m}^2$
$=\frac{22}{7}\times12.25\text{m}^2=22\times1.75\text{m}^2=38.5\text{m}^2$
breadth $(b) = 15m$
Area of the rectangular piece $= l \times b = 20 \times 15 = 300m^2$
Radius of semicircular portion $(r) = 3.5m$
Total area of $4$ quadrants
$=4\times\frac{1}{4}\times\pi\text{r}^2=\frac{22}{7}\times(3.5)^2\text{m}^2$
$=\frac{22}{7}\times12.25\text{m}^2=22\times1.75\text{m}^2=38.5\text{m}^2$
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