$t = \frac{d}{v}{\rm{\,\,also \,\,}}v \propto \sqrt T $
$\Rightarrow \frac{{{t_1}}}{{{t_2}}} = \frac{{{v_2}}}{{{v_1}}} = \sqrt {\frac{{{T_2}}}{{{T_1}}}} $
==> $\frac{2}{{{t_2}}} = \sqrt {\frac{{303}}{{283}}} $
$ \Rightarrow $${t_2}= 1.9 \,sec.$

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[$A$] The time $\mathrm{T}_{A 0}=\mathrm{T}_{\mathrm{OA}}$
[$B$] The velocities of the two pulses (Pulse $1$ and Pulse $2$) are the same at the midpoint of rope.
[$C$] The wavelength of Pulse $1$ becomes longer when it reaches point $A$.
[$D$] The velocity of any pulse along the rope is independent of its frequency and wavelength.