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[$A$] The time $\mathrm{T}_{A 0}=\mathrm{T}_{\mathrm{OA}}$
[$B$] The velocities of the two pulses (Pulse $1$ and Pulse $2$) are the same at the midpoint of rope.
[$C$] The wavelength of Pulse $1$ becomes longer when it reaches point $A$.
[$D$] The velocity of any pulse along the rope is independent of its frequency and wavelength.
So, $\mathrm{T}_{\mathrm{AO}}=\mathrm{T}_{\mathrm{OA}}$
Wavelength becomes longer when speed of the pulse increases.
${y_1} = 0.05\,\cos \,\left( {0.50\,\pi x - 100\,\pi t} \right)$
${y_2} = 0.05\,\cos \,\left( {0.46\,\pi x - 92\,\pi t} \right)$
then velocity is..... $m/s$