$(a)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\begin{array}{*{20}{c}}
{\,I} \\
|
\end{array}} \\
{C{H_3} - C - H} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ , Isopropyl iodide $(2^o)$
$(b)$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,H\,\,\,\,\,\,H\,\,\,\,\,H} \\
{\,\,\,|\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,|}
\end{array}} \\
{H - C - C - C - I} \\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,|\,} \\
{\,\,\,\,\,\,\,\,\,\,H\,\,\,\,\,\,H\,\,\,\,\,C{H_3}}
\end{array}$, sec- Butyl iodide $(2^o)$
$(c)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,C{H_3}} \\
|
\end{array}\,} \\
{{H_3}C - C - I} \\
{\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ , tert - Butyl iodide $(3^o)$
$(d)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,C{H_3}\,\,H\,\,} \\
{|\,\,\,\,\,\,\,\,\,|}
\end{array}} \\
{C{H_3} - C{H_2} - C - C - Cl} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,|\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,CH{\,_3}\,H\,\,\,\,\,\,}
\end{array}$, Neohexyl chloride $(1^o)$
Thus, $(d)$ is a primary $(1^o)$ halide.
$C{H_2} = C{H_2}\,\xrightarrow{{{O_2}/Ag}}\,X\,\xrightarrow{{473\,K}}\,Y$
$(I)\,\,CH_3CH_2OH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$
$(II)\,\,CH_3CH_2OH + HCl \rightarrow$
$(III)\,\,(CH_3)_3COH + HCl \rightarrow$
$(IV)\,\,(CH_3)_2CHOH + HCl \xrightarrow{{Anh.\,\,ZnC{l_2}}}$
વિધાન $I$ : પિક્રિક એસીડ એ $2,4,6$ - ટ્રાયનાઈટ્રોટોલ્યુઇન છે.
વિધાન $II$ : પિક્રિક એસીડ મેળવવા ફીનોલ $- 2,4 -$ ડાયસલ્ફોનીક એસીડ ની સાન્દ્ર $\mathrm{HNO}_3$ સાથે પ્રક્રિયા કરવામાં આવે છે.
ઉપરના વિધાનોના સંદર્ભમાં, નીચે આપેલા વિકલ્પોમાંથી સૌથી બંધબેસતો જવાબ પસંદ કરો.