(\(Zn\) reacts differently with very dilute HNO \(_{3}\) )
Reaction of \(Zn\) with conc. \(HNO_{3}\) \(\mathrm{Zn}+4 \mathrm{HNO}_{3}(\mathrm{conc.}) \longrightarrow \mathrm{Zn}\left(\mathrm{NO}_{3}\right)_{2}+2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{NO}_{2}\)
$(A)$ $O$
$(B)$ $S$
$(C)$ $Se$
$(D)$ $Te$
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