[મોલર દળ ${KCl}=74.5$ ]
$1000\, {~kg} \text { solvent } \longrightarrow 3.3 \times 74.5\, {gm} {KCl}$
$\quad\quad\quad\quad\quad\quad\quad \longrightarrow 245.85$
Weight of solution $=1245.85\, {gm}$
Volume of solution $=\frac{1245.85}{1.2}\, {ml}$
So molarity $=\frac{3.3 \times 1.2}{1245.85} \times 1000=3.17$
મોલર દળ $N =14\,g\,mol ^{-1} ; O =16\,g\,mol ^{-1} ; C =12\,g\,mol ^{-1} ; H =1\,g\,mol ^{-1}$;
(આપેલ : $Mg$ નો પરમાણ્વીય દળ $24\, g\, mol ^{-1} ; N _{ A }=6.02 \times 10^{23}\, mol ^{-1}$ )